12x^2+3x=14

Solution for 12x^2+3x=14 equation:

12x^2+3x=14

We move all terms to the left:

12x^2+3x-(14)=0

a = 12; b = 3; c = -14;
Δ = b2-4ac
Δ = 32-4·12·(-14)
Δ = 681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{681}}{2*12}=\frac{-3-\sqrt{681}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{681}}{2*12}=\frac{-3+\sqrt{681}}{24}
$